Question

a). [(7supra18-5supra12-1supta24):(-1 1supra24)-(-0,2)]:(-0,4)
si
b). [(27 supra32-7supra24-5supra36):(-17supra24)-(-0,8(3))]:(-0,25)

Answer 1

a)[(7/18-5/12-1/24):(-11/24)-(-0,2)]:(-0,4)=
=[((7•2)/36-(5•3)/36-1/24):(-11/24+0,2]:(-4/10)=
=[(14/36-15/36-1/24):(-11/24+2/10)]:(-2/5)=
=[(1/36-1/24):(-11/24+1/5)]•(-5/2)=
=[(2/72+3/72):((-11•5)/120+24/120]•(-5/2)=
=[-5/72:(-55/120+24/120)]•(-5/2)=
=[-5/72:(-31/120)]•(-5/2)=
=(5/72•120/31)•(-5/2)=
=(5/3•5/31)•(-5/2)=
=25/91•(-5/2)=-125/182

b)[(27/32-7/24-5/36):(-17/24)-(-0,8(3))]:(-0,25)=
=[(27/32-(7•3)/72-(5•2)/72):(-17/24+(83-8)/90)]:(-25/100))=
=[(27/32-21/72-10/72):(-17/24+75/90)]:(-1/4)=
=[(27/32-31/72):(-17/24+25/18)]:(-1/4)=
=[((27*9)-(31*4))/288:((-17*3)+(25*4))/72]:(-1,4)=
=[(243-124)/288:(-51+100)/72]:(-1/4)=
=(119/288:49/72):(-1/4)=
=(119/288*72/49):(-1/4)=
=(17/4*1/7)*(-4)=
=17/28*(-4)=
=-17/7=
=-2 intregi 3/7