Question

(a-933÷3+300)×2=978 ajutați.mă va rog nu imi da corect mie.

Answer 1

[tex] \it (a-933:3+300)\cdot2=978|_{:2} \Rightarrow a-311+300 = 489|_{+311} \Rightarrow \\ \\ \Rightarrow a+300 = 800 \Rightarrow a = 500 [/tex]

Answer 2

(a-933:3+300)•2=978

(a-311+300)•2=978

(a-11)•2=978

2(a-11)=978

a-11=978:2=489

a=489+11=500