Question

a)a:a+1+a:1+2+2(a:2)+3+3(a:3)=28
b)[200-81:(8+1)×10]-(6×7+8)-(6×7+3):9=a×(23+42:6):5×[(48+8):7-3×2]+9
c)(27+5+16):2×9-2×a=100
d)(96+16:4)-5(a+3)+100:10-10a=65


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Dau coroana!
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Help me!!

Answer 1

a) (a:a)+1+(a:1)+2+(2a:2)+3+(3a:3) = 28
Am pus in paranteza ce se face prima data
1+1+a+2+a+3+a = 28
7+3a = 28
3a=21
a=7
(7:7)+1+(7:1)+2+(2*7:2)+3+(3a:3) = 1+1+7+2+7+3+7 = 2+7+2+7+3+7 = 9+2+7+3+7 = 11+7+3+7 = 18+3+7 = 21+7 = 28

b) 200-81:(8+1)*10 - (6*7+8) - (6*7+3):9 =
200-81:9*10 - 50 - 45:9 =
200-9*10 - 50 - 5 =
200-90-50-5 =
110-50-5 =
60-5 = 55
a*(23+42:6):5*[(48+8):7-3*2]+9 = 55
30a : 5 * (56:7-6) = 46
6a * (8-6) = 46
6a*2 = 46
12a=46
a=3,8(3)

c) (27+5+16):2*9-2a = 100
48:2*9 - 2a = 100
24*9 - 2a = 100
216 - 2a = 100
2a = 116
a=58

d) (96+16:4) - 5(a+3) + 100:10 - 10a = 65
100 - 5a + 5*3 + 10 - 10a = 65
100 - 5a + 15 + 10 - 10a = 65
100 - 5a + 25 - 10a = 65
125 - 5a - 10a = 65
125 - (5a+10a) = 65
15a = 60
a=4