Question

a) Aflati cel mai mic numar natural care impartit la numerele 15, 30 si 45 da, de fiecare data, un cat diferit de zero si 13 . Multumesc !

Answer 1

a:15=c1 r 13
a:30=c2 r 13
a: 45 =c3 r 13

a= 15 c1 +13
a= 30 c2 +13
a= 45 c3 +13

a-13 = 15 c1
a-13=30 c2
a-13= 45 c3

15 = 3 ×5
30 = 2 ×3 ×5
45 = 3² × 5

[15,30,45] = 2 ×3² ×5 = 90
a-13 = 90 ⇒ a= 103