Question

a)Analizati aceste ecuatii si identificati compusii organici A,B,C,D din schema de reactii de mai jos , stiind ca masa molara a compusului A reprezinta 76,433 % din masa moleculara a compusului B. Scrieti ecuatiile reactiilor chimice : A+ PCl5 -> B + POCl3 + HCl A+ NaOH -> C + H2O B+ C -> D + NaCl D + H2O -> 2A B + H2O -> A + HCl
b) Calculati masa de compus A necesara obtinerii a 61,2 g de compus D .

Answer 1

Răspuns:

SE STIE

R-COOH+PCL5---> R-COCl+POCl3+HCl

M,A=M,R+ 45

M,clorura acida=M,B=M,R+63,5

M,B- M,A=18,5

M,A= 0,76433M,B

rezolvand sistenul de doua ecuatii, rezulta : M,A= 60g/mol M,B=78,5g/mol

din M,A= 60=M,R+45---> M,R=15--> R=-CH3---> A= CH3COOH

CH3COOH(A)+PCl5----> CH3COCl(B)+POCL3+HCl

CH3COOH+NaOH---->CH3COONa(C)+H2O

CH3COCl+CH3COONa---> CH3-COOCOCH3(D)+NaCl

CH3COOCOCH3+H2O---> 2CH3COOH

CH3COCl+H2O---->CH3COOH+HCl

M,A= 60g/mol

M,D=102g/mol===> niu=m/M= 61,2/102mol=0,6mol

2mol CH3COOH............1mol D

X............................................0,6

x= 1,2mol---> m= niuxM=1,2x60g=72g D

Explicație: