Question

A (aranjamente) de x luate cate 5=18* A de (x-2) luate cate 4.

Answer 1

X!/(x-5)!=18*(x-2)!/(x-6)!, (x-4)(x-3)(x-2)(x-1)x=18*(x-5)(x-4)(x-3)(x-2), (x-1)x=18(x-5), x^2-19x+90=0. Rezolvi ecuatia şi afli soluţiile.