Question

a) Aratati ca abc+bca+cab divide 37.....b) Determinati nr de forma abc stiind ca abc+bca+cab=555.

Answer 1

a) abc+bca+cab I 37
    100a+10b+c+100b+10c+a+100c+10a+b=
   =111a+111b+111c=
   =111(a+b+c)=
   =37x3x(a+b+c)=multiplu de 37

b) abc+bca+cab=555
    100a+10b+c+100b+10c+a+100c+10a+b=555
     111a+111b+111c=555
     111(a+b+c)=555
     a+b+c=555:111
     a+b+c=5
     abc={104,113,122,131,140,203,212,221,230,302,311,320,401,410,500)