Question

a+b=1149. b+c=891. a+c=960. aflati valoarea fiecarui numar

Answer 1

2a+2b+2c = 1149+891+960
2(a+b+c) = 3000
a+b+c = 3000:2
a+b+c = 1500
1149+c = 1500
c = 1500-1149
c = 351
a+891 = 1500
a = 1500-891
a = 609
b+960 = 1500
b = 1500-960
b = 540
proba
609+540+351 = 1149+351 = 1500

Answer 2

a+b=1149      
b+c=891        
a+c=960

(a+b)+(b+c)+(a+c)=1149+891+960
2a+2b+2c=3000
2(a+b+c)=3000
a+b+c=3000:2
a+b+c=1500
daca b+c=891 
a=1500-891
a=609

daca a+b=1149
b=1149-609
b=540

daca a+c=960      
c=960-609
c=351