Question

a+b=20; b+c=32; a+c=28; sa s calculeze c-b; c-a; b-a

Answer 1

a+b+b+c+a+c = 20+32+28=80
2x(a+b+c) = 80
a+b+c=80:2
a+b+c=40

a= (a+b+c) - (b+c)
a= 40- 32
a=8

b= (a+b) - a
b=20 - 8
b=12

c=(b+c) -b
c=32-12
c=20

c-b = 20 - 12
c-b=8

c-a =20-8
c-a=12

b-a= 12- 8
b-a = 4