Question

a=b+72 (a+b):(a-b)=5 rest 2

Answer 1

(b+72+b):(b+72-b)=5 rest 2
(2b+72):72=5 r 2
2b+72=5×72+2
2b+72=362
2b=362-72
2b=290
b=290÷2
b=145
a=145+72
a=217

Answer 2

Cerinta:  Sa se determine cele doua numere (  a si b ).

a = b + 72

( a + b ) : ( a - b ) = 5 rest 2

a - b = 72 → diferenta numerelor ⇔ am dedus-o din relatia a = b + 72

( a + b ) : 72 = 5 rest 2

a + b = 5 × 72 + 2 → teorema impartirii cu rest

a + b = 360 + 2

a + b = 362 → suma numerelor

( b + 72 ) + b = 362

2 × b = 362 - 72

2 × b = 290

b = 290 : 2

b = 145

a = 145 + 72  ⇒   a = 217