Question

a+b:a-b=1 rest 12 iar (a+b)+(a-b)=64

Answer 1

a+b:a-b=1 rest 12
a+b=a-b×1+12
a+b=a-b+12

(a+b)+(a-b)=64
inlocuim pe a+b
a-b+12+a-b=64
2×(a-b)+12=64
2×(a-b)=64-12
2×(a-b)=52
a-b=52:2
a-b=26


inlocuim pe a-b
a+b=a-b+12
a+b=26+12
a+b=38

proba

38+26=64 ( Adevarat )

38:26=1 rest12 ( Adevarat )