Question

a+b+c=104 , a cu 14 mai mare decat b,c cu 3 mai mic decat b

Answer 1

|____|..+3..|...+14...| a

|____|..+3..| b

|____| c



104 - (3+14+3)=
104 - 20=
84

1 + 1 + 1 = 3 (segmente egale)

84 : 3 = 28 (valoarea unui segment)

a = 1 ×28+3+14=28+3+14=31+14=45

b = 1 ×28+3 = 28 + 3 = 31

c = 1 × 28 = 28

verificare:
a + b + c = 45 + 31 + 28 = 104