Question

A+b+c=111 b÷a=3r3 c÷b=2r2

Answer 1

[tex]a+b+c=111 \\ b:a=3\:rest\:3\rightarrow b=3a+3 \\ c:b=2\:rest\:2\rightarrow c=2b+2=2(3a+3)+2=6a+6+2=6a+8\\ a+3a+3+6a+8=111\\ 10a+11=111\\ 10a=111-11=100\\ a=100:10=10\\ b=3a+3=3\cdot10+3=33\\ c=2b+2=2\cdot33+2=68[/tex]