Question

a+b+c=156.c=10+b.a×2+b×3+4×c=488.sa se afle.a.b.c?

Answer 1

a+b+c = 156
c = 10+b
a×2+b×3+4×c = 488
2×(a+b+c)+b+2×c = 488
2×156+b+2×(10+b) = 488
312+b+20+2×b = 488
3×b = 488-312-20
3×b = 156
b = 156:3
b = 52
c = 10+52 = 62
a = 156-(52+62) = 156-114 = 42

Verificare:
42 + 52 + 62 = 156

a = 42
b = 52
c = 62