Question

a+b+c=2768. a=(bx2)+15. c=(a+b):3

Answer 1

Stim ca c=(a+b):3 dar a=2×b+15

=> c=(2×b+15+b):3=(3×b+15):3

C=3(b+5):3=b+5

Ne ducem in relatia a+b+c=2768 si inlocuim a si c in functie de b

=> 2×b+15+b+b+5=2768

=> 4×b+20=2768=> 4×b=2768-20=>4×b=2748 => b=687

Mergem in a si inlocuim b-ul

=> a=2×b+15=2×687+15=1389

c=b+5=1389+5=1394