Question

a+b+c=297
a:b=2r25
a:c=11r8
sa se afle numerele

Answer 1

a:b=2 R=25
a=2b+25⇔2b=a-25
a:c=11 R=8
a=11c+8
 a+b+c=297/ ·2⇔ 2a+2b+2c=594⇔ 22c+16+a-25+2c=594⇔ 22c+16+11c+8-25+2c=594⇔35c-1=594⇔ 35c=595⇔ c=17 ⇒ a=11·17+8⇔ a=195 ⇒2b=195-25=170⇔b=85

Answer 2

a+b+c=297
a:b=2r25⇒a=2b+25
a:c=11r8⇒a=11c+8
_______________________
a=?b=?c=?
_______________________
2b+25=11c+8|-8
2b+17=11c
c=2b+17/11
2b+25+b+(2b+17)/11=297
3b+(2b+17)/11=272
Amplificam cu 11:
33b/11+(2b+17)/11=2992/11|·11
33b+2b+17=2992
35b=2975
b=85
a=2·85+25
a=170+25
a=195
c=297-(195+85)
c=297-280
c=17