Question

a+b+c=5 , atunci b²+c²+2bc+2(a - 9/2) ≥ 0 Repede...va rogggg

Answer 1

a+b+c=5  ⇒ b+c=5-a
$( b-c)^{2}$=$(5-a)^{2}$
$bx^{2}$+$c^{2}$+2bc=$(5-a)x^{2}$
vom avea $(5-a)^{2}$+2a-9≥0
25-10a+$a^{2}$+2a-9≥0
$a^{2} -8a+16$≥0
$(a-4)^{2}$≥0 adevarat