Question

a+b+c=52 2a=3b=4c a=? b=? c=?​

Answer 1

Explicație pas cu pas:

$a+b+c=52 \\ 2a=3b=4c = k$

=>

$2a = k = > a = \frac{k}{2} \\ 3b = k = > b = \frac{k}{3} \\ 4c = k = > c = \frac{k}{4}$

=>

$\frac{k}{2} + \frac{k}{3} + \frac{k}{4} = 52 \\ \frac{6k + 4k + 3k}{12} = 52$

$\frac{13k}{12} = 52 = > k = 48$

=>

$a = \frac{48}{2} = > a = 24 \\ b = \frac{48}{3} = > b = 16 \\ c = \frac{48}{4} = > c = 12$

Answer 2

Răspuns:

Explicație pas cu pas:

2a = 3b = 4c = k

a = 1/2k

b = 1/3k

c = 1/4k

a + b + c = 52

Înlocuim

1/2k + 1/3k + 1/4k = 52 | × 12

6k + 4k + 3k = 624

13k = 624

k = 624 : 13 = 48

a = 1/2 × 48 = 48/2 = 24

b = 1/3 × 48 = 48/3 = 16

c = 1/4 × 48 = 48/4 = 12