Question

a+b+c=61, c= 2a+18, c>b cu 25, afla numerele

Answer 1

a+b+c = 61
c = 2a+18
b = (2a+18) - 25
a+2a+18 - 25 +2a+18 = 61
5a = 61-18+25-18
5a = 43+25-18
5a = 68-18
5a = 50
a = 50:5
a = 10
b = (2a+18)-25
b = (2*10+18)-25
b = (20+18)-25
b = 38-25
b = 13
c = 2a+18
c = 2*10+18
c = 20+18
c = 38

Answer 2

a + b + c = 61
c = 2a + 18
b = 2a + 18 - 25
a + 2a + 18 - 25 + 2a + 18 = 61
5a = 61 - 18 + 25 - 18
5a = 50
a = 50 : 5
a = 10
b = 2a + 18 - 25
b = 2 x 10 + 18 - 25
b = 20 + 18 - 25
b = 13
c = 2 a + 18
c = 2 x 10 + 18
c = 38
verificam
10 + 13 + 38 = 61