Question

a+b+c=88 ,a:b=4 rest 3, c>a cu 2 ,a=? ,c=? ,b=?

Answer 1

a+b+c=88
a:b=4 rest 3, rezulta a=4b+3, rezulta  b=(a-3)/4
c=a+2 
inlocuim in relatia a+b+c=88
a+(a-3)/4+a+2=88
2a+(a-3)/4=88-2
(8a+a-3)/4=86
9a-3=86x4
9a=344+3
a=347/9
a=38,(5)
b=(347/9-3)/4=(347-27)/36=320/36
b=8,(8)
c=347/9+2=(347+18)/9=365/9
c=40,(5)