Question

a+b+c=984. 1:4a=1:3b. c=b-a. a,b,c,=...?

Answer 1

a+b+c=984
a/4 = b/3 ⇒ a = 4b/3
c = a - b
inlocuim in prima ecuatie:
4b/3 + b + (4b/3 - b) = 984
aducem la acelasi numitor:
4b + 3b + (4b - 3b) = 2952
4b + 3b + b = 2952
b = 369

apoi:
a = 4b/3 ⇒ 4 * 369/3 ⇒ a = 492
a + b +c = 984
492 + 369 + c = 984
c = 123

PROBA:
492 + 369 + 123 = 984