Question

(a+b+c+d)×3=36.a×4=x,b×2=x,c+1=x,d-2=x.Cât este a,b,c,d?

Answer 1

ax4=x
a=x:4
bx2=x
b=x:2
c+1=x
c=x-1
d-2=x
d=x+2
(x:4+x:2+x-1+x+2)x3=36
(x:4+x:2+x-1+x+2)=36:3
x:4+x:2+x-1+x+2=12
$\frac{x}{4}+ \frac{x}{2}+x-1+x+2=12$
[tex] \frac{x}{4}+ \frac{x}{2}+x+x=12+1-2 [/tex]
$\frac{x}{4}+ \frac{x}{2} +2x=11$
aducem la acelasi numitor comun adica 4
x+2x+8x=44
11x=44
x=44:11
x=4

a=x:4
a=4:4
a=1

b=x:2
b=4:2
b=2

c=x-1
c=4-1
c=3

d=x+2
d=4+2
d=6

v: (1+2+3+6)x3=36
     12x3=36