Question

a+b+c+d=54 a,b,c,d = numere consecutive impare

Answer 1

a+b+c+d=54

a=a

b=a+1

c=a+2

d=a+3

a+a+1+a+2+a+3=54

4a+(1+2+3)=54

4a+(3+3)=54

4a+6=54

4a=54-6

4a=48

a=48:4

a=12

b=a+1

b=12+1

b=13

c=a+2

c=12+2

c=14

d=a+3

d=12+3

d=15

Rezolvare:12+13+14+15=

25+29=54