Question

a+b+c+d+e=80 , a<b cu 10, c=a+b, d>a cu 6, e=2d

Answer 1

a=b+10
c=a+b=b+10+b=2b+10
d=a+6 d=b+10+6=b+16
e=2d  e=2(b+16)=2b+32

b+10+2b+10+b+16+2b+32=80
6b+68=80
6b=12
b=2, a=2+10=12, c=12+2=14, d=12+6=18, e=18x2=36