Question

(a,b,c) d. p (3,7,9 )
a+b+c--38

Answer 1

a , b , c d.p cu 3 , 7 , 9
=>
$\frac{a}{3} = \frac{b}{7} = \frac{c}{9} = k \\ = > a = 3k \: \: b = 7k \: \: c = 9k$
Acum inlocuiesti in suma:
$3k + 7k + 9k = 38 \\ 19k = 38 \\ k = 2$
Si acum afli a b c:

a = 3k = 6
b = 7k = 14
c = 9k = 18