Question

a,b,c invers proportional cu 6,8,10 stiind ca 1/a³ + 1/b³ + 1/c³ = 64
Va rog!!! URGENT!!​

Answer 1

{a,b,c} i.p {6,8,10} => a/1/6 = b/1/8 = c/1/10 = k

deci a = k/6, b = k/8, c = k/10

1/a³ + 1/b³ + 1/c³ = 64

1/(k/6)³ + 1/(k/8)³ + 1/(k/10)³ = 64

216/k³ + 512/k³ + 1000/k³ = 64

1728 = 64k³

k³ = 1728/64

k = ∛27

k = 3

a = 3/6 = 1/2

b = 3/8

c = 3/10