Question

a.Care dintre numerele x=7(a+1)+3a+1 si y=4(a+1)+6(a+2) ,unde a este numarul natural ,este cel mai mare ?
b.Care dintre numerele x=17(a+1)+7a+1 si y=6(a+1)+2(9a+2) . unde a este numar natural , este mai mic ?

Answer 1

x=7(a+1)+3a+1x=7a+7+3a+1=10a+8
y=4(a+1)+6(a+2)y=4a+4+6a+12=10a+16

Deci y>x

b). x=17(a+1)+7a+1
x=17a+17+7a+1=24a+18

y=6(a+1)+2(9a+2)
y=6a+6+18a+4=24a+10

Deci x>y

Answer 2

a)x=7(a+1)+3a+1=7a+7+3a+1=10a+8
y=4(a+1)+6(a+2)=4a+4+6a+12=10a+16
xeste mai mic decit y

b)x=17(a+1)+7a+1=17a+17+7a+1+24a+18
y=6(a+1)+2(9a+2)=6a+6+18a+4=24a+10
x este mai mare decit y