Question

a. Care este masa de CO2 care contine aceeasi cantitate de oxigen ca si 4 moli de CaO?
b. cate molecule de apa vor contine aceeasi cantitate de hidrogen ca si 3,4 de NH3?
c. cati moli de H2SO4 contin aceeasi cantitate de oxigen ca si 1,89g de HNO3?
d. calculati masa de SO3 care contine aceleasi numar de molecule ca si cel continut in 640g de SO2.
e. cate molecule de apa va contine solutia obtinuta prin dizolvarea a 25g de CuSO4• 5H2O in 75g de apa ?​

Answer 1

Răspuns:

Explicație:

a.

4moli CaO

masa de CO2

-se afla g CaO

MCaO= 40 + 16=56----> 56g/moli

m= 4moli . 56g/moli = 224g CaO

-se afla masa de O din CaO

56 g CaO-------16gO

224g ------------------x

x= 224 . 16 : 56= 64g O

-se afla masa de CO2 care contine 64 g O

M CO2= 12 + 2.16=44------> 44g/moli

44g  CO2---------------32g O

yg CO2-----------------64gO

y= 44. 64 : 32=  88 g CO2

b.

3,4g NH3

molecule H2O

MNH3= 14 + 3=17----> 17g/moli

17g NH3------------3 g H

3,4g Nh3------------xgH

x= 3,4 . 3 : 17= 0,6 g H

MH2O= 2 + 16=18----> 18g/moli

18 g H2 O------------2g H

yg H2O-----------------0,6g H

y= 18 . 0,6 : 2= 5,4 gH2 O

n= 5,4g : 18g/moli = 0,3 moli H2O

1mol H2O--------------6,022.10²³ molecule H2O

0,3moli H2O----------------------z

z= 0,3 . 6,022.10²³= 1 , 8066 . 10²³molecule H2 O

c.

1,89g HNO3

moli H2SO4

M HNO3= 1 + 14 + 3.16= 63-----> 63g/moli

63g HNO3---------------48g O

1,89g HNO3----------------xg O

x= 1,89 . 48 : 63= 1,44 g O

M H2SO4= 2 + 32 + 4.16=98------> 98g/moli

98g H2 SO4------------------64g O

ygH2SO4-----------------------1,44gO

y= 98 . 1,44 : 64= 2,205 g H2SO4

n= 2,205g : 98g/moli=0,0225moli H2SO4

d.

640 g SO2

masa de SO3

MSO2= 32 + 2.16=64-----> 64g/moli

n= m : M

n= 640g : 64g/moli= 10 moli SO2

1mol SO2------------------------6,022.10²³molecule SO2

10 moli SO2---------------------------x

x= 10 . 6,022.10²³= 60, 22.10²³ moleculeSO2

MSO3= 32 + 3.16= 80-----> 80g/moli

1mol SO3-------------------6,022.10²³molecule SO3

zmoli SO3------------------------60,22.10²³ molecule SO3

z= 60,22.10²³ : 6,022.10²³ = 10 moli SO3

m= n .M

m= 10moli . 80g/moli= 800g SO3

e.

md= 25g  CuSO4 . 5H2O

mapa= 75g

M=64 + 32 + 4.16 + 5.18= 160 + 90

mapa = 90 g

250g CuSO4 .5H2O-----------------90g H2O

25g--------------------------------------------a

a= 25 .90 : 250= 9g H2O

mapa total= 75 + 9= 84g

n = 84g : 18g/moli=4,66moli H2O

1mol H2O---------------6,022.10 ²³ molecule H2O

4,66moli H2O-------------------------x

x= 4,66 . 6,022.10²³= 28,06. .10²³molecule H2O