Question

a) compara numerele a= (3²)³•3⁴:3⁴cu b=27
b) ordoneaza crescator numerele: 11 supra 3,3 intregi si 5 supra 6 si 3,(3).




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Answer 1

Răspuns:

a) compara numerele a= (3²)³•3⁴:3⁴cu b=27

a= (3²)³•3⁴:3⁴

a=3⁶3⁴:3⁴

a=3⁶⁺⁴⁻⁴

a=3⁶

b=27=>b=3³

3⁶ > 3³ => a > b

b) ordoneaza crescator numerele: 11 supra 3,3 intregi si 5 supra 6 si 3,(3).

11/3=11:3=3,(6)

3 intregi si 5 supra 6=(3×6+5)/6=23/6=23:6=3,8(3)

3,(3)

3,(3) , 3,(6) , 3,8(3)

Answer 2

Explicație pas cu pas:

a)

$a = {( {3}^{2} )}^{3} \cdot {3}^{4} : {3}^{4} = {3}^{6}$

$b = 27 = {3}^{3}$

${3}^{6} > {3}^{3} \implies a > b$

b)

$\frac{11}{3} = 3 \frac{2}{3} = 3 \frac{4}{6}$

$3 \frac{5}{6}$

$3,(3) = 3\frac{3}{9} = 3 \frac{1}{3} = 3 \frac{2}{6}$

$3 \frac{2}{6} < 3 \frac{4}{6} < 3 \frac{5}{6}$

=>

$3,(3) < \frac{11}{3} < 3 \frac{5}{6}$