Question

a)d:a=d:b=d:c=4,iar,a+b+c+d=21
b)a:d=b:d=c:d=4,iar,a+b+c+d=13
Este cu metoda grafica

Answer 1

a)
a |____|
b |____|
c |____|
d |____|____|____|____|
avem 7 segmente egale = 21
21 :7 = 3 ( un segment)
a = 3
b = 3
c = 3
d = 4×3 = 12

verificare:
3+3+3+12 = 21

b)
a |____|____|____|____|
b |____|____|____|____|
c |____|____|____|____|
d |____|
avem 13 segmente egale = 13
13 :13 = 1 ( un segment egal)
a = 4×1 = 4
b = 4×1 = 4
c = 4×1 = 4
d = 1

Verificare:
4+4+4+1 = 13