Question

a)Impartiti numarul 6 in parti invers proportionale cu 2 si 3.
b)Impartiti-l pe 6 in parti invers proportionale cu 1 supra 2 si 1 supra 3.

Answer 1

x si y partile 

x+y=6  

a)  {x;y}  invers prop.  {2,3}  la numitor inversele lui 2 si 3

$\frac{x}{ \frac{1}{2} }= \frac{y}{ \frac{1}{3} } = \frac{x+y}{ \frac{1}{2} + \frac{1}{3} } = \frac{6}{ \frac{3+2}{6} } =6: \frac{5}{6} = \frac{36}{5}$

$\frac{x}{ \frac{1}{2} } = \frac{36}{5}$ ⇒   x=36/10 =3,6

3,6+y=6  ⇒y= 2,4

b) $\frac{x}{2} = \frac{y}{3} = \frac{x+y}{2+3} = \frac{6}{5}$

si mai departe ca la a)