Question

a) Indicati configuratia electronice ale atomilor de Al (13) si Cr (24)
b) Precizati nr straturi, substraturi si orbitali
c) Calculati nr de electroni ''p'' din 5,4g Al

Multumesc!

Answer 1

Rapuns a) si b)
(13)Al:           1s2-2s2-2p6-3s2-3p1
orbitali = 7
straturi = 3
substraturi = 5 

(24) Cr       1s2 2s2 2p6 3s2 3p6 3d6 4s1 3d5(↑↑↑↑↑)
orbitali = 15
straturi = 4
substraturi = 7

c)    27 g Al......................................6,023*10 la 23 atomi Al
       5,4 g................................................x
x = 1,2046*10 la 23 atomi Al

1 atom Al..........................................................7 electroni ''p''
1,2046*10 la 23 atomi Al...............................    y

y = 7 * 1,2046*10 la 23 electroni ''p''