Question

a jutati va rog dau coroana
numai a)b)c)​

Answer 1

Explicație pas cu pas:

a) 2×{92+8×[1004+4×(8:2×2-4×2:2)]}

2×{92+8×[1004+4×(8-4×1)]}

2×{92+8×[1004+4×(8-4)]}

2×{92+8×[1004+4×4]}

2×{92+8×[1004+16]}

2×{92+8×1020]

2×{92+8160}

2×8252

16504

c) 8-7:{6-5:[4-3:(2-2:2)]}

8-7:{6-5:[4-3:(2-1)]}

8-7:{6-5:[4-3:1]}

8-7:{6-5:[4-3]}

8-7:{6-5:1}

8-7:{6-5}

8-7÷1

8-7

1

b) (2019×2018-2018×2017)×2019⁰:1²⁰¹⁸

2018×(2019-2017)×1:1

(orice numar la puterea 0 da 1,iar 1 ridicat la orice putere tot 1 e)

2018×(2019-2017)÷1

2018×(2019-2017)

2018×2

4036