Question

a=log in baza 3 din 8 * log in baza 4 din 9. Ma poate ajuta cineva va rog?

Answer 1

Salut,

$A=log_32^3\cdot log_{2^2}3^2=3\cdot log_32\cdot2\cdot log_{2^2}3=6\cdot log_32\cdot\dfrac{1}{log_32^2}=\\\\=6\cdot log_32\cdot\dfrac{1}{2\cdot log_32}=\dfrac{6}2=3.$

Green eyes.