Question

A={n ∈ N | n+2|3n₊11} URGENT VA ROG

Answer 1

(n+2)l(3n+11). }
(n+2)l(n+2)=>(n+2)l(3n+6)} =>(n+2)l[(3n+11)-(3n+6)] =>(n+2)l5
Divizorii naturali ai lui 5 sunt : 1;5
1. n+2=1
n=-1 Fals
2.n+2=5
n=3
A={3}