Question

a= rad 52 + rad 208
a - 19 < 0 ​

Answer 1

Răspuns:

$\sqrt{52} = \sqrt{ {2}^{2} \times 13} = 2 \sqrt{13}$

$\sqrt{208} = \sqrt{ {2}^{4} \times 13} = 4 \sqrt{13}$

$a = 6 \sqrt{13}$

rad13 = aprox. 3,6

6 × 3,6 = 21,63

a > 19