Question

A.Radical 3+2 radical 3-5 radical 3
B.-(3 radical6+radical 6)+11 radical 6

Answer 1

A> $\sqrt{3}+2\sqrt{3}-5\sqrt{3}=3\sqrt{3}-5\sqrt{3}=-2\sqrt{3}$
B> $-(3\sqrt{6}+\sqrt{6})+11\sqrt{6}=-4\sqrt{6}+11\sqrt{6}=7\sqrt{6}$
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Answer 2

A: -2 radical 3
B:  7 radical din 6