Question

A={radical din 12;- radical⅔; radical3⅕; (-radical din 2)puterea-1; -radical din 7; radical 0,(3)}.

Answer 1

Explicație pas cu pas:

$A = \Big\{ \sqrt{12} ; - \sqrt{ \frac{2}{3} } ; \sqrt{3 \frac{1}{3} } ; {( - \sqrt{2} )}^{ - 1} ; - \sqrt{7} ; \sqrt{0.(3)} \Big\}$

$\sqrt{12} = 2 \sqrt{2} \\ - \sqrt{ \frac{2}{3} } = - \sqrt{ \frac{6}{9} } = - \frac{ \sqrt{6} }{3} \\ \sqrt{3 \frac{1}{3} } = \sqrt{ \frac{10}{3} } = \sqrt{ \frac{30}{9} } = \frac{ \sqrt{30} }{3} \\ {( - \sqrt{2} )}^{ - 1} = - \frac{1}{ \sqrt{2} } = - \frac{ \sqrt{2} }{2} \\ - \sqrt{7} \\ \sqrt{0,(3)} = \sqrt{ \frac{3}{9} } = \frac{ \sqrt{3} }{3}$