Question

a=radical din 20 supra 20, b= radical din 5 supra 6, compara nr​

Answer 1

$a=\frac{\sqrt{20} }{20} =\frac{2\sqrt{5} }{20} =\frac{\sqrt{5} }{10}=\frac{3\sqrt{5} }{30} \\b=\frac{\sqrt{5} }{6} =\frac{5\sqrt{5} }{30} \\\frac{3\sqrt{5} } {30}<\frac{5\sqrt{5} }{30}; a<b$