Question

a=radical98-radical32
b=radical162+radical18
Sa se calculeze
Mg=?
Ma=?

Answer 1

Răspuns:

Ai rezolvarea in foto.......

Answer 2

Răspuns:

Explicație pas cu pas:

$a=\sqrt{98}-\sqrt{32}=\sqrt{49*2}-\sqrt{16*2}=7\sqrt{2}-4\sqrt{2}=3\sqrt{2} \\b=\sqrt{162}+\sqrt{18}=\sqrt{81*2}+\sqrt{9*2}=9\sqrt{2}+3\sqrt{2}=12\sqrt{2}\\Mg=\sqrt{a*b}=\sqrt{3\sqrt{2}*12\sqrt{2}}=\sqrt{36*(\sqrt{2})^{2} }=6\sqrt{2}\\Ma=\frac{a+b}{2}=\frac{3\sqrt{2} +12\sqrt{2}}{2}=\frac{15\sqrt{2} }{2}$