Question

A)Rezolvati ecuatia (x-1)²-2(X-2)=(X-3)(x+3)
b)Rezolvati inecuatia 4(x+3)<2(x+5)+8
Rezultatele trebuie sa fie 7/3 si b -infinit , -1

Answer 1

1 $x^{2} -2x + 1 - 2x + 4 = x^{2} - 9$
[tex] x^{2} - 4x + 5 = x^{2} - 9 =\ \textgreater \ -4x = -9-5 =\ \textgreater \ x = \frac{-14}{-4} = 7/2[/tex]
 

2. 4x+12<2x+10+8 
4x-2x<18-12
2x<6
x<3
x apartine (-infinit, 3)