Question

a) Scrieti numarul 2^2005 ca produs de doua puteri.

b) Scrieti numarul 4^1001 ca putere cu baza 2.

c) Calculati:
(3x 2^2004- 2^2005) :4^1001.

Mulumesc anticipat!

Answer 1

a) 2 la 1002 ×2 la 1003
b) 2 la a2-a tutul la 1001=2 la 2002
c)(3×2la 2004-2 la 2005):2 la 2002
2la 2004(3-2):2la 2002
2la 2004:2la 2002=2la a 2-a=4

Answer 2

a)
$2^{2005} = 2^{2} *2^{2003}$
b)
 $4^{1001}= (2^{2} )^{1001} = 2^{2002}$
c)
[tex] 2^{2004} (3-2): 2^{2002} = 2^{2004} *2: 2^{2002} = 2^{2005} : 2^{2002} = 2^{3} [/tex]