Question

a si c de la 17 va rog mult de tot​

Answer 1

Răspuns:

a) -124

c) $-\frac{6}{37}$

Explicație pas cu pas:

a)

$(\sqrt{2} )^{4} * (\frac{1}{2} )^{2} - \sqrt{\frac{16}{25} } * (-\sqrt{\frac{25}{2} } )^{4}$

$= 4*\frac{1}{4} - \frac{4}{5} * (\frac{25}{2} )^{2}$

$= 1 - \frac{4*625}{5*4}$

= 1 - 125

= -124

c)

$(-\frac{3\sqrt{6} }{28} ) : (\frac{5}{\sqrt{24} } + \frac{19}{7\sqrt{6} } - \frac{5}{\sqrt{150} } - \frac{2}{\sqrt{384} } )$

$= (-\frac{3\sqrt{6} }{28} ) : (\frac{5}{2\sqrt{6} } + \frac{19}{7\sqrt{6} } - \frac{5}{5\sqrt{6} } - \frac{2}{8\sqrt{6} } )$

$= (-\frac{3\sqrt{6} }{28} ) : (\frac{5*140 + 19*40 - 5*56 - 2* 35}{280\sqrt{6} } )$

$= (-\frac{3\sqrt{6} }{28} ) : \frac{700+760 - 280 - 70}{280\sqrt{6} }$

$= (-\frac{3\sqrt{6} }{28} ) * \frac{280\sqrt{6} }{1110}$

$= -\frac{3*6*10}{1110} = - \frac{180}{1110} = -\frac{6}{37}$