Question

A)Știind că 3x+2y+4z=30,determinati 4z+43+2y+27+3x.

B)Știind ca x+3+y+4+z+5=12,determinati 2012+x+y+z.

Answer 1

3x+2y+4z=30
4z+43+2y+27+3x. =( 3x+2y+4z)+43+27=30+43+27=100

x+3+y+4+z+5=12 ;⇒ (x+y+z)+9=12⇒  (x+y+z=12-9⇒ (x+y+z= 3
2012+x+y+z=2012+3=2015