Question

A Supra 3 = 2b supra 5 = 3c supra 4
a+b+c=41

Answer 1

A Supra 3 = 2b supra 5 = 3c supra 4=k
a=3k
2b=5k
3c=4k
12k=41=>k=3.41(6)
a=10.24(9)
2b=17.08(3)=>b=8.541(6)
3c=13.(6)=>c=4.(5)

Answer 2

[tex]\dfrac{a}{3}=\dfrac{2b}{5}=\dfrac{3c}{4}=k\Rightarrow a=3k,b=\dfrac{5k}{2}, c=\dfrac{4k}{3}\\ a+b+c=41\\ 3k+\dfrac{5k}{2}+\dfrac{4k}{3}=41|\cdot 6\\ 18k+15k+8k=6\cdot 41\\ 41k=6\cdot 41\Rightarrow k=6\\ a=3k\Rightarrow \boxed{a=18}\\ b=\dfrac{5k}[2}\Rightarrow \boxed{b=15}\\ c=\dfrac{4k}{3}\Rightarrow \boxed{c=8}\\ R:\text{Numerele cautate sunt 18,15 si 8.}[/tex]