Question

a)$3(x- \frac{11}{5}=0,75$
b)$0,2(x+ \frac{16}{5}=4,2$

Answer 1

a)  3$(x- \frac{11}{5})=0,75=> x- \frac{11}{5} =0,25=>x= \frac{25}{100} + \frac{11}{5}=> \\ =>x= \frac{245}{100} =>x=2,45$
b)$0,2(x+ \frac{16}{5} )=4.2=>x+ \frac{16}{5} =21=>x= \frac{121}{5} \\ =>x= 24,2$