Question

a) trei numere consecutive , cu suma 4281;

Answer 1

a+a+1+a+2=4281

3a+3=4281/-3

3a=4278/:3

a=1426=> a+1=1427
a+2=1428

Answer 2

a |___|
b |___|1|
c |___|2|

        $1p+2p=3~parti$
        $4281-3=4278$
         $4278:3=1426~(a)$
        $1426+1=1427~(b)$
        $1426+2=1428~(c)$