Question

a) (x+1)^2+(x-2)^2=0

b) (x+1)^2+(x+2)^2=3

^= la PUTERE a 2
abonare,coroana,15puncte

Answer 1

(x+1)²≥0
(x-2)²≥0
pt ca
(x+1)²+(x-2)²=0 estte necesar ca
(x+1)²=0⇒ x+1=0;⇒ x=-1
si
(x-2)²=0⇒x-2=0⇒x=2
-1=2 absurd deci S=∅

b)

x²+2x+1+x²+4x+4=3
2x²+6x+5=3 | :2
2x²+3x+2=0
a=2
b=3
c=2
Δ=9-4*2*2=9-16=-7<0
Ecuatia nu are solutii reale
S⊄R
si nu se rezolva la clasa a 8-a