Question

a)(x+1)^2=x(x-1)+4;
b)(x+2)^2=(x-2)(x+2);
c)2(x-3)^2=x(x-2)+(x+1)^2;
d)(x+3)(x-3)=(x+2)^2+x+2;
e)x^2+(x+1)^2=(x+2)(3x+2)-x(3+x);
f)(x-1)^2+2(x+2)^2=(3-x)^2+2(x^2+6).
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Dau coroană!!!

Answer 1

Răspuns:

Explicație pas cu pas:

a)(x+1)^2=x(x-1)+4

x^2 + 2x + 1 = x^2 - x + 4

3x = 3

x = 1

______________

b)(x+2)^2=(x-2)(x+2)

x^2 + 4x + 4 = x^2 - 4

4x = -8

x = -2

________________

c)2(x-3)^2=x(x-2)+(x+1)^2

2x^2 - 12x + 18 = x^2 - 2x + x^2 + 2x + 1

12x = 17

x = 17/12

_______________

d)(x+3)(x-3)=(x+2)^2+x+2

x^2 - 9 = x^2 + 4x + 4 + x + 2

5x = -15

x = -3

_______________

e)x^2+(x+1)^2=(x+2)(3x+2)-x(3+x)

x^2 + x^2 + 2x + 1 = 3x^2 + 2x + 6x + 4 - 3x - x^2

2x^2 + 2x + 1 = 2x^2 + 5x + 4

3x = -3

x = -1

_________________

f)(x-1)^2+2(x+2)^2=(3-x)^2+2(x^2+6)

x^2 - 2x + 1 + 2x^2 + 8x + 8 = 9 - 6x + x^2 + 2x^2 + 12

3x^2 + 6x + 9 = 3x^2 - 6x + 21

12x = 12

x = 1