Question

a) (x-1) totul la a doua
b) (2x+5y) totul la a doua
c) (4y-7) totul la a doua
e) (4 radical din 3-2 ) totul la a doua

Answer 1

Răspuns:

Explicație pas cu pas:

(x - 1)^2 = x^2 - 2x + 1

(2x + 5y)^2 = 4x^2 + 20xy + 25y^2

(4y - 7)^2 = 16y^2 - 56y + 49

(4√3 - 2)^2 = 48 - 16√3 + 4 = 52 - 16√3

Answer 2

Răspuns:

Explicație pas cu pas:

$a) (x-1)^2=x^2-1^2=x^2-2x+1\\\\b)(2x+5y)^2=(2x)^2+2*2x*5+(5y)^2=4x^2+4x*5+25y^2=4x^2+20xy+25y^2\\\\c) (4y-7)^2=(4y)^2-2*4y*7+7^2=16y^2-8y*7+49=16y^2-56y+49\\\\d)(4\sqrt{3} -2)^2=(4\sqrt{3} )^2-2*4\sqrt{3} *2+2^2=16\sqrt{3^2} -8\sqrt{3} *2+4=16*3-16\sqrt{3} +4=48+4-16\sqrt{3} =52-16\sqrt{3}$

Succes! :)